Base | Representation |
---|---|
bin | 11000101101011000110000… |
… | …11100000000010101001111 |
3 | 21010101110211010202111211111 |
4 | 30112230120130000111033 |
5 | 24110220203030200041 |
6 | 311321344401432451 |
7 | 14305435520113525 |
oct | 1426543034002517 |
9 | 233343733674744 |
10 | 54336041256271 |
11 | 1634987082a265 |
12 | 611683233b727 |
13 | 2441b361c4748 |
14 | d5bc425a2315 |
15 | 643612489981 |
hex | 316b1870054f |
54336041256271 has 2 divisors, whose sum is σ = 54336041256272. Its totient is φ = 54336041256270.
The previous prime is 54336041256251. The next prime is 54336041256317. The reversal of 54336041256271 is 17265214063345.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54336041256271 - 25 = 54336041256239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54336041256251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27168020628135 + 27168020628136.
It is an arithmetic number, because the mean of its divisors is an integer number (27168020628136).
Almost surely, 254336041256271 is an apocalyptic number.
54336041256271 is a deficient number, since it is larger than the sum of its proper divisors (1).
54336041256271 is an equidigital number, since it uses as much as digits as its factorization.
54336041256271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 49.
The spelling of 54336041256271 in words is "fifty-four trillion, three hundred thirty-six billion, forty-one million, two hundred fifty-six thousand, two hundred seventy-one".
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