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5433631031344 = 24339601939459
BaseRepresentation
bin100111100010001110110…
…1001011100000000110000
3201020110011002101220101111
41033010131221130000300
51203011034021000334
615320101534243104
71100365304466205
oct117043551340060
921213132356344
105433631031344
11180543207653a
127390a8056494
1330550a121049
1414adbc2ddcac
159651b8d5064
hex4f11da5c030

5433631031344 has 10 divisors (see below), whose sum is σ = 10527660123260. Its totient is φ = 2716815515664.

The previous prime is 5433631031329. The next prime is 5433631031369. The reversal of 5433631031344 is 4431301363345.

It is a super-2 number, since 2×54336310313442 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5433631031297 and 5433631031306.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 169800969714 + ... + 169800969745.

It is an arithmetic number, because the mean of its divisors is an integer number (1052766012326).

Almost surely, 25433631031344 is an apocalyptic number.

It is an amenable number.

5433631031344 is a deficient number, since it is larger than the sum of its proper divisors (5094029091916).

5433631031344 is a wasteful number, since it uses less digits than its factorization.

5433631031344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339601939467 (or 339601939461 counting only the distinct ones).

The product of its (nonzero) digits is 466560, while the sum is 40.

Adding to 5433631031344 its reverse (4431301363345), we get a palindrome (9864932394689).

The spelling of 5433631031344 in words is "five trillion, four hundred thirty-three billion, six hundred thirty-one million, thirty-one thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 339601939459 679203878918 1358407757836 2716815515672 5433631031344