Base | Representation |
---|---|
bin | 11000101101100010001100… |
… | …00110100011011100010111 |
3 | 21010101221212212002211012001 |
4 | 30112301012012203130113 |
5 | 24110311034200232101 |
6 | 311323542514340131 |
7 | 14306005113531226 |
oct | 1426610606433427 |
9 | 233357785084161 |
10 | 54341102352151 |
11 | 16350a2867652a |
12 | 611780528a647 |
13 | 24424618c5034 |
14 | d5c1a2808cbd |
15 | 64380b95d901 |
hex | 316c461a3717 |
54341102352151 has 2 divisors, whose sum is σ = 54341102352152. Its totient is φ = 54341102352150.
The previous prime is 54341102352091. The next prime is 54341102352169. The reversal of 54341102352151 is 15125320114345.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54341102352151 - 237 = 54203663398679 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54341102352151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54341102392151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27170551176075 + 27170551176076.
It is an arithmetic number, because the mean of its divisors is an integer number (27170551176076).
Almost surely, 254341102352151 is an apocalyptic number.
54341102352151 is a deficient number, since it is larger than the sum of its proper divisors (1).
54341102352151 is an equidigital number, since it uses as much as digits as its factorization.
54341102352151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 54341102352151 its reverse (15125320114345), we get a palindrome (69466422466496).
The spelling of 54341102352151 in words is "fifty-four trillion, three hundred forty-one billion, one hundred two million, three hundred fifty-two thousand, one hundred fifty-one".
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