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5434113484781 is a prime number
BaseRepresentation
bin100111100010011101001…
…1001110110011111101101
3201020111101201020002002022
41033010322121312133231
51203013031023003111
615320221451035525
71100413253333042
oct117047231663755
921214351202068
105434113484781
11180565a438993
1273920173bba5
13305586071657
1414b0264091c9
1596548e342db
hex4f13a6767ed

5434113484781 has 2 divisors, whose sum is σ = 5434113484782. Its totient is φ = 5434113484780.

The previous prime is 5434113484769. The next prime is 5434113484819. The reversal of 5434113484781 is 1874843114345.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4418996783881 + 1015116700900 = 2102141^2 + 1007530^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5434113484781 is a prime.

It is a super-2 number, since 2×54341134847812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5434113484721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717056742390 + 2717056742391.

It is an arithmetic number, because the mean of its divisors is an integer number (2717056742391).

Almost surely, 25434113484781 is an apocalyptic number.

It is an amenable number.

5434113484781 is a deficient number, since it is larger than the sum of its proper divisors (1).

5434113484781 is an equidigital number, since it uses as much as digits as its factorization.

5434113484781 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5160960, while the sum is 53.

The spelling of 5434113484781 in words is "five trillion, four hundred thirty-four billion, one hundred thirteen million, four hundred eighty-four thousand, seven hundred eighty-one".