Search a number
-
+
5434324032014 = 22717162016007
BaseRepresentation
bin100111100010100011011…
…1101000001101000001110
3201020111221101101222120222
41033011012331001220032
51203013443423011024
615320254411511342
71100421421056263
oct117050675015016
921214841358528
105434324032014
111805758275169
12739260158552
133055ba87c607
1414b04637526a
159655c67385e
hex4f146f41a0e

5434324032014 has 4 divisors (see below), whose sum is σ = 8151486048024. Its totient is φ = 2717162016006.

The previous prime is 5434324031971. The next prime is 5434324032017. The reversal of 5434324032014 is 4102304234345.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×54343240320143 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5434324032017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1358581008002 + ... + 1358581008005.

It is an arithmetic number, because the mean of its divisors is an integer number (2037871512006).

Almost surely, 25434324032014 is an apocalyptic number.

5434324032014 is a deficient number, since it is larger than the sum of its proper divisors (2717162016010).

5434324032014 is a wasteful number, since it uses less digits than its factorization.

5434324032014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2717162016009.

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 5434324032014 its reverse (4102304234345), we get a palindrome (9536628266359).

The spelling of 5434324032014 in words is "five trillion, four hundred thirty-four billion, three hundred twenty-four million, thirty-two thousand, fourteen".

Divisors: 1 2 2717162016007 5434324032014