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54343315433 = 1142611159423
BaseRepresentation
bin110010100111000111…
…010010111111101001
312012021021112110022102
4302213013102333221
51342243342043213
640544233503145
73632451362651
oct624707227751
9165237473272
1054343315433
1121057426240
12a647571ab5
135180846b64
1428b74d1361
151630d33158
hexca71d2fe9

54343315433 has 8 divisors (see below), whose sum is σ = 59297581056. Its totient is φ = 49391377200.

The previous prime is 54343315393. The next prime is 54343315459. The reversal of 54343315433 is 33451334345.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 54343315433 - 210 = 54343314409 is a prime.

It is a super-4 number, since 4×543433154334 (a number of 44 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54343315493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 532841 + ... + 626582.

It is an arithmetic number, because the mean of its divisors is an integer number (7412197632).

Almost surely, 254343315433 is an apocalyptic number.

It is an amenable number.

54343315433 is a deficient number, since it is larger than the sum of its proper divisors (4954265623).

54343315433 is a wasteful number, since it uses less digits than its factorization.

54343315433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1163695.

The product of its digits is 388800, while the sum is 38.

Adding to 54343315433 its reverse (33451334345), we get a palindrome (87794649778).

The spelling of 54343315433 in words is "fifty-four billion, three hundred forty-three million, three hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 11 4261 46871 1159423 12753653 4940301403 54343315433