Base | Representation |
---|---|
bin | 11000101101100111101000… |
… | …00010000001101111010101 |
3 | 21010102020102012221001211101 |
4 | 30112303310002001233111 |
5 | 24110333023210313414 |
6 | 311325144234310101 |
7 | 14306140325533465 |
oct | 1426636402015725 |
9 | 233366365831741 |
10 | 54344020401109 |
11 | 1635219585293a |
12 | 611829a588331 |
13 | 244280831511a |
14 | d5c39c19bba5 |
15 | 64392cc15a74 |
hex | 316cf4081bd5 |
54344020401109 has 2 divisors, whose sum is σ = 54344020401110. Its totient is φ = 54344020401108.
The previous prime is 54344020401103. The next prime is 54344020401133. The reversal of 54344020401109 is 90110402044345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50943592200484 + 3400428200625 = 7137478^2 + 1844025^2 .
It is a cyclic number.
It is not a de Polignac number, because 54344020401109 - 211 = 54344020399061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54344020401103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27172010200554 + 27172010200555.
It is an arithmetic number, because the mean of its divisors is an integer number (27172010200555).
Almost surely, 254344020401109 is an apocalyptic number.
It is an amenable number.
54344020401109 is a deficient number, since it is larger than the sum of its proper divisors (1).
54344020401109 is an equidigital number, since it uses as much as digits as its factorization.
54344020401109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
The spelling of 54344020401109 in words is "fifty-four trillion, three hundred forty-four billion, twenty million, four hundred one thousand, one hundred nine".
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