Base | Representation |
---|---|
bin | 110010100111011001… |
… | …001000010101000101 |
3 | 12012021121022222002011 |
4 | 302213121020111011 |
5 | 1342301041142331 |
6 | 40544522014221 |
7 | 3632536203301 |
oct | 624731102505 |
9 | 165247288064 |
10 | 54347990341 |
11 | 2105a0295a7 |
12 | a649047371 |
13 | 51817c2988 |
14 | 28b7d8ad01 |
15 | 16314583b1 |
hex | ca7648545 |
54347990341 has 2 divisors, whose sum is σ = 54347990342. Its totient is φ = 54347990340.
The previous prime is 54347990329. The next prime is 54347990413. The reversal of 54347990341 is 14309974345.
Together with next prime (54347990413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33764062500 + 20583927841 = 183750^2 + 143471^2 .
It is a cyclic number.
It is not a de Polignac number, because 54347990341 - 211 = 54347988293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54347990441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27173995170 + 27173995171.
It is an arithmetic number, because the mean of its divisors is an integer number (27173995171).
Almost surely, 254347990341 is an apocalyptic number.
It is an amenable number.
54347990341 is a deficient number, since it is larger than the sum of its proper divisors (1).
54347990341 is an equidigital number, since it uses as much as digits as its factorization.
54347990341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 54347990341 in words is "fifty-four billion, three hundred forty-seven million, nine hundred ninety thousand, three hundred forty-one".
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