Base | Representation |
---|---|
bin | 100111100010111110010… |
… | …0110111111011001000001 |
3 | 201020121021010021112200201 |
4 | 1033011330212333121001 |
5 | 1203022314400202340 |
6 | 15320524010045201 |
7 | 1100452631431525 |
oct | 117057446773101 |
9 | 21217233245621 |
10 | 5435224225345 |
11 | 180607a4197a2 |
12 | 739471719801 |
13 | 305702212ca5 |
14 | 14b0cdb41d85 |
15 | 965b16dc79a |
hex | 4f17c9bf641 |
5435224225345 has 8 divisors (see below), whose sum is σ = 6541973812800. Its totient is φ = 4335042885360.
The previous prime is 5435224225303. The next prime is 5435224225357.
5435224225345 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5435224225345 - 213 = 5435224217153 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5435224225295 and 5435224225304.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1642060045 + ... + 1642063354.
It is an arithmetic number, because the mean of its divisors is an integer number (817746726600).
Almost surely, 25435224225345 is an apocalyptic number.
It is an amenable number.
5435224225345 is a deficient number, since it is larger than the sum of its proper divisors (1106749587455).
5435224225345 is a wasteful number, since it uses less digits than its factorization.
5435224225345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3284123735.
The product of its digits is 5760000, while the sum is 46.
The spelling of 5435224225345 in words is "five trillion, four hundred thirty-five billion, two hundred twenty-four million, two hundred twenty-five thousand, three hundred forty-five".
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