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543534202435361 is a prime number
BaseRepresentation
bin111101110010101110110101…
…1000011110011011100100001
32122021111100210002220101100212
41323211131223003303130201
51032220231021310412421
65204000055425423505
7222326023142200154
oct17345355303633441
92567440702811325
10543534202435361
11148206619404a15
1250b646a079ab95
131a439094820537
1498312a5267c9b
1542c888a4cbe5b
hex1ee576b0f3721

543534202435361 has 2 divisors, whose sum is σ = 543534202435362. Its totient is φ = 543534202435360.

The previous prime is 543534202435337. The next prime is 543534202435363. The reversal of 543534202435361 is 163534202435345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 330256802274961 + 213277400160400 = 18172969^2 + 14604020^2 .

It is a cyclic number.

It is not a de Polignac number, because 543534202435361 - 230 = 543533128693537 is a prime.

Together with 543534202435363, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (543534202435363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271767101217680 + 271767101217681.

It is an arithmetic number, because the mean of its divisors is an integer number (271767101217681).

Almost surely, 2543534202435361 is an apocalyptic number.

It is an amenable number.

543534202435361 is a deficient number, since it is larger than the sum of its proper divisors (1).

543534202435361 is an equidigital number, since it uses as much as digits as its factorization.

543534202435361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552000, while the sum is 50.

The spelling of 543534202435361 in words is "five hundred forty-three trillion, five hundred thirty-four billion, two hundred two million, four hundred thirty-five thousand, three hundred sixty-one".