Base | Representation |
---|---|
bin | 100111100100011110110… |
… | …1111110000101010100101 |
3 | 201020220121221110220221121 |
4 | 1033020331233300222211 |
5 | 1203100433404331023 |
6 | 15322221321013541 |
7 | 1100626135514260 |
oct | 117107557605245 |
9 | 21226557426847 |
10 | 5438464527013 |
11 | 1807492499361 |
12 | 73a0169242b1 |
13 | 305aca62275b |
14 | 14b31a21bcd7 |
15 | 96700debd5d |
hex | 4f23dbf0aa5 |
5438464527013 has 4 divisors (see below), whose sum is σ = 6215388030880. Its totient is φ = 4661541023148.
The previous prime is 5438464526951. The next prime is 5438464527031. The reversal of 5438464527013 is 3107254648345.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5438464527013 - 217 = 5438464395941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5438464527113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388461751923 + ... + 388461751936.
It is an arithmetic number, because the mean of its divisors is an integer number (1553847007720).
Almost surely, 25438464527013 is an apocalyptic number.
It is an amenable number.
5438464527013 is a deficient number, since it is larger than the sum of its proper divisors (776923503867).
5438464527013 is an equidigital number, since it uses as much as digits as its factorization.
5438464527013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 776923503866.
The product of its (nonzero) digits is 9676800, while the sum is 52.
The spelling of 5438464527013 in words is "five trillion, four hundred thirty-eight billion, four hundred sixty-four million, five hundred twenty-seven thousand, thirteen".
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