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54401142151 = 179099303749
BaseRepresentation
bin110010101010100011…
…111000110110000111
312012102022100100122201
4302222203320312013
51342403143022101
640554101135331
73634053035656
oct625243706607
9165368310581
1054401142151
1121087032314
12a6629ba547
13518c812855
1428c106519d
151635e56e01
hexcaa8f8d87

54401142151 has 4 divisors (see below), whose sum is σ = 54401625000. Its totient is φ = 54400659304.

The previous prime is 54401142139. The next prime is 54401142157. The reversal of 54401142151 is 15124110445.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 54401142151 - 25 = 54401142119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54401142157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27225 + ... + 330973.

It is an arithmetic number, because the mean of its divisors is an integer number (13600406250).

Almost surely, 254401142151 is an apocalyptic number.

54401142151 is a deficient number, since it is larger than the sum of its proper divisors (482849).

54401142151 is a wasteful number, since it uses less digits than its factorization.

54401142151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 482848.

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 54401142151 its reverse (15124110445), we get a palindrome (69525252596).

The spelling of 54401142151 in words is "fifty-four billion, four hundred one million, one hundred forty-two thousand, one hundred fifty-one".

Divisors: 1 179099 303749 54401142151