Base | Representation |
---|---|
bin | 1111110101010100011… |
… | …11001111000111110001 |
3 | 1221000012211101000200011 |
4 | 13322222033033013301 |
5 | 32403124113000423 |
6 | 1053530435254521 |
7 | 54206241463114 |
oct | 7725217170761 |
9 | 1830184330604 |
10 | 544022000113 |
11 | 19a79a266779 |
12 | 89527a4a441 |
13 | 3c3bb555657 |
14 | 1c48ba3057b |
15 | e240788b0d |
hex | 7eaa3cf1f1 |
544022000113 has 2 divisors, whose sum is σ = 544022000114. Its totient is φ = 544022000112.
The previous prime is 544022000059. The next prime is 544022000141. The reversal of 544022000113 is 311000220445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 538144017889 + 5877982224 = 733583^2 + 76668^2 .
It is a cyclic number.
It is not a de Polignac number, because 544022000113 - 213 = 544021991921 is a prime.
It is not a weakly prime, because it can be changed into another prime (544022000513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272011000056 + 272011000057.
It is an arithmetic number, because the mean of its divisors is an integer number (272011000057).
Almost surely, 2544022000113 is an apocalyptic number.
It is an amenable number.
544022000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
544022000113 is an equidigital number, since it uses as much as digits as its factorization.
544022000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 22.
Adding to 544022000113 its reverse (311000220445), we get a palindrome (855022220558).
The spelling of 544022000113 in words is "five hundred forty-four billion, twenty-two million, one hundred thirteen", and thus it is an aban number.
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