Base | Representation |
---|---|
bin | 1111110101010100011… |
… | …11001111001000001101 |
3 | 1221000012211101000201012 |
4 | 13322222033033020031 |
5 | 32403124113001031 |
6 | 1053530435255005 |
7 | 54206241463154 |
oct | 7725217171015 |
9 | 1830184330635 |
10 | 544022000141 |
11 | 19a79a2667a4 |
12 | 89527a4a465 |
13 | 3c3bb555679 |
14 | 1c48ba3059b |
15 | e240788b2b |
hex | 7eaa3cf20d |
544022000141 has 2 divisors, whose sum is σ = 544022000142. Its totient is φ = 544022000140.
The previous prime is 544022000113. The next prime is 544022000161. The reversal of 544022000141 is 141000220445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 442231650025 + 101790350116 = 665005^2 + 319046^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-544022000141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544022000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272011000070 + 272011000071.
It is an arithmetic number, because the mean of its divisors is an integer number (272011000071).
Almost surely, 2544022000141 is an apocalyptic number.
It is an amenable number.
544022000141 is a deficient number, since it is larger than the sum of its proper divisors (1).
544022000141 is an equidigital number, since it uses as much as digits as its factorization.
544022000141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 23.
Adding to 544022000141 its reverse (141000220445), we get a palindrome (685022220586).
The spelling of 544022000141 in words is "five hundred forty-four billion, twenty-two million, one hundred forty-one", and thus it is an aban number.
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