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544022000141 is a prime number
BaseRepresentation
bin1111110101010100011…
…11001111001000001101
31221000012211101000201012
413322222033033020031
532403124113001031
61053530435255005
754206241463154
oct7725217171015
91830184330635
10544022000141
1119a79a2667a4
1289527a4a465
133c3bb555679
141c48ba3059b
15e240788b2b
hex7eaa3cf20d

544022000141 has 2 divisors, whose sum is σ = 544022000142. Its totient is φ = 544022000140.

The previous prime is 544022000113. The next prime is 544022000161. The reversal of 544022000141 is 141000220445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 442231650025 + 101790350116 = 665005^2 + 319046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-544022000141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544022000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272011000070 + 272011000071.

It is an arithmetic number, because the mean of its divisors is an integer number (272011000071).

Almost surely, 2544022000141 is an apocalyptic number.

It is an amenable number.

544022000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

544022000141 is an equidigital number, since it uses as much as digits as its factorization.

544022000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 23.

Adding to 544022000141 its reverse (141000220445), we get a palindrome (685022220586).

The spelling of 544022000141 in words is "five hundred forty-four billion, twenty-two million, one hundred forty-one", and thus it is an aban number.