Base | Representation |
---|---|
bin | 1111110101010100100… |
… | …00111010100100100111 |
3 | 1221000012212012101101211 |
4 | 13322222100322210213 |
5 | 32403124221041411 |
6 | 1053530452532251 |
7 | 54206245305214 |
oct | 7725220724447 |
9 | 1830185171354 |
10 | 544022440231 |
11 | 19a79a537406 |
12 | 89528021087 |
13 | 3c3bb67aa8a |
14 | 1c48bb06b0b |
15 | e240824221 |
hex | 7eaa43a927 |
544022440231 has 2 divisors, whose sum is σ = 544022440232. Its totient is φ = 544022440230.
The previous prime is 544022440211. The next prime is 544022440249. The reversal of 544022440231 is 132044220445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 544022440231 - 233 = 535432505639 is a prime.
It is a super-2 number, since 2×5440224402312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 544022440193 and 544022440202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544022440201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272011220115 + 272011220116.
It is an arithmetic number, because the mean of its divisors is an integer number (272011220116).
Almost surely, 2544022440231 is an apocalyptic number.
544022440231 is a deficient number, since it is larger than the sum of its proper divisors (1).
544022440231 is an equidigital number, since it uses as much as digits as its factorization.
544022440231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30720, while the sum is 31.
Adding to 544022440231 its reverse (132044220445), we get a palindrome (676066660676).
The spelling of 544022440231 in words is "five hundred forty-four billion, twenty-two million, four hundred forty thousand, two hundred thirty-one".
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