Base | Representation |
---|---|
bin | 100111100101011001001… |
… | …0100111010101100110111 |
3 | 201021002200020211210220101 |
4 | 1033022302110322230313 |
5 | 1203113440112041003 |
6 | 15323143350414531 |
7 | 1101025455413311 |
oct | 117126224725467 |
9 | 21232606753811 |
10 | 5440420424503 |
11 | 18082a6553069 |
12 | 73a481961447 |
13 | 30604c8c7b4c |
14 | 14b463cb67b1 |
15 | 967b799c11d |
hex | 4f2b253ab37 |
5440420424503 has 4 divisors (see below), whose sum is σ = 5566941829768. Its totient is φ = 5313899019240.
The previous prime is 5440420424489. The next prime is 5440420424507. The reversal of 5440420424503 is 3054240240445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5440420424503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5440420424507) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63260702568 + ... + 63260702653.
It is an arithmetic number, because the mean of its divisors is an integer number (1391735457442).
Almost surely, 25440420424503 is an apocalyptic number.
5440420424503 is a deficient number, since it is larger than the sum of its proper divisors (126521405265).
5440420424503 is a wasteful number, since it uses less digits than its factorization.
5440420424503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126521405264.
The product of its (nonzero) digits is 307200, while the sum is 37.
Adding to 5440420424503 its reverse (3054240240445), we get a palindrome (8494660664948).
The spelling of 5440420424503 in words is "five trillion, four hundred forty billion, four hundred twenty million, four hundred twenty-four thousand, five hundred three".
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