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54413251141 = 113513479357
BaseRepresentation
bin110010101011010010…
…000101001001000101
312012110011010120001211
4302223102011021011
51342414243014031
640555212451421
73634261001104
oct625322051105
9165404116054
1054413251141
1121092952a47
12a666a79b71
135192192332
1428c28d803b
151637049bb1
hexcab485245

54413251141 has 4 divisors (see below), whose sum is σ = 54413844012. Its totient is φ = 54412658272.

The previous prime is 54413251063. The next prime is 54413251153. The reversal of 54413251141 is 14115231445.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 40379294916 + 14033956225 = 200946^2 + 118465^2 .

It is a cyclic number.

It is not a de Polignac number, because 54413251141 - 233 = 45823316549 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54413251181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126166 + ... + 353191.

It is an arithmetic number, because the mean of its divisors is an integer number (13603461003).

Almost surely, 254413251141 is an apocalyptic number.

It is an amenable number.

54413251141 is a deficient number, since it is larger than the sum of its proper divisors (592871).

54413251141 is a wasteful number, since it uses less digits than its factorization.

54413251141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 592870.

The product of its digits is 9600, while the sum is 31.

Adding to 54413251141 its reverse (14115231445), we get a palindrome (68528482586).

The spelling of 54413251141 in words is "fifty-four billion, four hundred thirteen million, two hundred fifty-one thousand, one hundred forty-one".

Divisors: 1 113513 479357 54413251141