Base | Representation |
---|---|
bin | 1111110101100010100… |
… | …11010011000111000111 |
3 | 1221000112002100201120011 |
4 | 13322301103103013013 |
5 | 32403344432134133 |
6 | 1053550311251051 |
7 | 54212210661025 |
oct | 7726123230707 |
9 | 1830462321504 |
10 | 544140505543 |
11 | 19a850147648 |
12 | 8955b679a87 |
13 | 3c409c781cb |
14 | 1c49d67b715 |
15 | e24ad966cd |
hex | 7eb14d31c7 |
544140505543 has 2 divisors, whose sum is σ = 544140505544. Its totient is φ = 544140505542.
The previous prime is 544140505477. The next prime is 544140505549. The reversal of 544140505543 is 345505041445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 544140505543 - 229 = 543603634631 is a prime.
It is a super-2 number, since 2×5441405055432 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 544140505496 and 544140505505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544140505549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272070252771 + 272070252772.
It is an arithmetic number, because the mean of its divisors is an integer number (272070252772).
Almost surely, 2544140505543 is an apocalyptic number.
544140505543 is a deficient number, since it is larger than the sum of its proper divisors (1).
544140505543 is an equidigital number, since it uses as much as digits as its factorization.
544140505543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480000, while the sum is 40.
Adding to 544140505543 its reverse (345505041445), we get a palindrome (889645546988).
The spelling of 544140505543 in words is "five hundred forty-four billion, one hundred forty million, five hundred five thousand, five hundred forty-three".
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