Base | Representation |
---|---|
bin | 100111100101110111110… |
… | …1101011001110001110111 |
3 | 201021012100000122112121112 |
4 | 1033023233231121301313 |
5 | 1203123042231102211 |
6 | 15323433455305235 |
7 | 1101063132001103 |
oct | 117135755316167 |
9 | 21235300575545 |
10 | 5441450253431 |
11 | 180878489a855 |
12 | 73a70a81b21b |
13 | 30618507a18a |
14 | 14b52098a903 |
15 | 968280c188b |
hex | 4f2efb59c77 |
5441450253431 has 2 divisors, whose sum is σ = 5441450253432. Its totient is φ = 5441450253430.
The previous prime is 5441450253427. The next prime is 5441450253439. The reversal of 5441450253431 is 1343520541445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5441450253431 - 22 = 5441450253427 is a prime.
It is a super-2 number, since 2×54414502534312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5441450253439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2720725126715 + 2720725126716.
It is an arithmetic number, because the mean of its divisors is an integer number (2720725126716).
Almost surely, 25441450253431 is an apocalyptic number.
5441450253431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5441450253431 is an equidigital number, since it uses as much as digits as its factorization.
5441450253431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 5441450253431 its reverse (1343520541445), we get a palindrome (6784970794876).
The spelling of 5441450253431 in words is "five trillion, four hundred forty-one billion, four hundred fifty million, two hundred fifty-three thousand, four hundred thirty-one".
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