Base | Representation |
---|---|
bin | 110010101011100001… |
… | …100110011110110101 |
3 | 12012110102210021022011 |
4 | 302223201212132311 |
5 | 1342421313213421 |
6 | 40555440004221 |
7 | 3634340405212 |
oct | 625341463665 |
9 | 165412707264 |
10 | 54417319861 |
11 | 21095181923 |
12 | a668300671 |
13 | 5192c88268 |
14 | 28c3276b09 |
15 | 16375a04e1 |
hex | cab8667b5 |
54417319861 has 2 divisors, whose sum is σ = 54417319862. Its totient is φ = 54417319860.
The previous prime is 54417319837. The next prime is 54417319877. The reversal of 54417319861 is 16891371445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52594542225 + 1822777636 = 229335^2 + 42694^2 .
It is a cyclic number.
It is not a de Polignac number, because 54417319861 - 221 = 54415222709 is a prime.
It is a super-2 number, since 2×544173198612 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54417319661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27208659930 + 27208659931.
It is an arithmetic number, because the mean of its divisors is an integer number (27208659931).
Almost surely, 254417319861 is an apocalyptic number.
It is an amenable number.
54417319861 is a deficient number, since it is larger than the sum of its proper divisors (1).
54417319861 is an equidigital number, since it uses as much as digits as its factorization.
54417319861 is an evil number, because the sum of its binary digits is even.
The product of its digits is 725760, while the sum is 49.
The spelling of 54417319861 in words is "fifty-four billion, four hundred seventeen million, three hundred nineteen thousand, eight hundred sixty-one".
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