Base | Representation |
---|---|
bin | 11000101111111010110100… |
… | …01101010000011110111111 |
3 | 21010200210101111211110211001 |
4 | 30113331122031100132333 |
5 | 24113131343233014242 |
6 | 311425333513111131 |
7 | 14314635523366306 |
oct | 1427753215203677 |
9 | 233623344743731 |
10 | 54423044032447 |
11 | 16382757606772 |
12 | 612b6733b84a7 |
13 | 244a0c0094cac |
14 | d621373bb43d |
15 | 645a0561eeb7 |
hex | 317f5a3507bf |
54423044032447 has 2 divisors, whose sum is σ = 54423044032448. Its totient is φ = 54423044032446.
The previous prime is 54423044032429. The next prime is 54423044032477. The reversal of 54423044032447 is 74423044032445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54423044032447 - 223 = 54423035643839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54423044032397 and 54423044032406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54423044032477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27211522016223 + 27211522016224.
It is an arithmetic number, because the mean of its divisors is an integer number (27211522016224).
Almost surely, 254423044032447 is an apocalyptic number.
54423044032447 is a deficient number, since it is larger than the sum of its proper divisors (1).
54423044032447 is an equidigital number, since it uses as much as digits as its factorization.
54423044032447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5160960, while the sum is 46.
The spelling of 54423044032447 in words is "fifty-four trillion, four hundred twenty-three billion, forty-four million, thirty-two thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •