Base | Representation |
---|---|
bin | 110010101011111100… |
… | …101000010000001011 |
3 | 12012110221010020021211 |
4 | 302223330220100023 |
5 | 1342430121430003 |
6 | 41000251513551 |
7 | 3634454544463 |
oct | 625374502013 |
9 | 165427106254 |
10 | 54424405003 |
11 | 21099181011 |
12 | a66a7588b7 |
13 | 5194599157 |
14 | 28c419cba3 |
15 | 1637eee96d |
hex | cabf2840b |
54424405003 has 2 divisors, whose sum is σ = 54424405004. Its totient is φ = 54424405002.
The previous prime is 54424404989. The next prime is 54424405019. The reversal of 54424405003 is 30050442445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54424405003 - 213 = 54424396811 is a prime.
It is not a weakly prime, because it can be changed into another prime (54424405093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27212202501 + 27212202502.
It is an arithmetic number, because the mean of its divisors is an integer number (27212202502).
Almost surely, 254424405003 is an apocalyptic number.
54424405003 is a deficient number, since it is larger than the sum of its proper divisors (1).
54424405003 is an equidigital number, since it uses as much as digits as its factorization.
54424405003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 31.
Adding to 54424405003 its reverse (30050442445), we get a palindrome (84474847448).
The spelling of 54424405003 in words is "fifty-four billion, four hundred twenty-four million, four hundred five thousand, three".
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