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544253524141 is a prime number
BaseRepresentation
bin1111110101110000000…
…10011011100010101101
31221000210222000122221011
413322320002123202231
532404112400233031
61054005425505221
754215052424225
oct7727002334255
91830728018834
10544253524141
1119a8a8a20148
12895914a2211
133c4274c9512
141c4b069b085
15e255c6d6b1
hex7eb809b8ad

544253524141 has 2 divisors, whose sum is σ = 544253524142. Its totient is φ = 544253524140.

The previous prime is 544253524093. The next prime is 544253524151. The reversal of 544253524141 is 141425352445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 490635806116 + 53617718025 = 700454^2 + 231555^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-544253524141 is a prime.

It is a super-3 number, since 3×5442535241413 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 544253524094 and 544253524103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544253524151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272126762070 + 272126762071.

It is an arithmetic number, because the mean of its divisors is an integer number (272126762071).

Almost surely, 2544253524141 is an apocalyptic number.

It is an amenable number.

544253524141 is a deficient number, since it is larger than the sum of its proper divisors (1).

544253524141 is an equidigital number, since it uses as much as digits as its factorization.

544253524141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384000, while the sum is 40.

Adding to 544253524141 its reverse (141425352445), we get a palindrome (685678876586).

The spelling of 544253524141 in words is "five hundred forty-four billion, two hundred fifty-three million, five hundred twenty-four thousand, one hundred forty-one".