Base | Representation |
---|---|
bin | 1010001000110011… |
… | …11100101100001101 |
3 | 112001022020202021221 |
4 | 11010121330230031 |
5 | 42121302321143 |
6 | 2300022123341 |
7 | 251605336204 |
oct | 50431745415 |
9 | 15038222257 |
10 | 5442620173 |
11 | 2343243101 |
12 | 107a880551 |
13 | 689773513 |
14 | 398b9c23b |
15 | 21cc382ed |
hex | 14467cb0d |
5442620173 has 2 divisors, whose sum is σ = 5442620174. Its totient is φ = 5442620172.
The previous prime is 5442620149. The next prime is 5442620177. The reversal of 5442620173 is 3710262445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2845902409 + 2596717764 = 53347^2 + 50958^2 .
It is a cyclic number.
It is not a de Polignac number, because 5442620173 - 213 = 5442611981 is a prime.
It is a super-2 number, since 2×54426201732 = 59244228695093099858, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5442620177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2721310086 + 2721310087.
It is an arithmetic number, because the mean of its divisors is an integer number (2721310087).
Almost surely, 25442620173 is an apocalyptic number.
It is an amenable number.
5442620173 is a deficient number, since it is larger than the sum of its proper divisors (1).
5442620173 is an equidigital number, since it uses as much as digits as its factorization.
5442620173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
The square root of 5442620173 is about 73774.1158740652. The cubic root of 5442620173 is about 1759.0141876201.
The spelling of 5442620173 in words is "five billion, four hundred forty-two million, six hundred twenty thousand, one hundred seventy-three".
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