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544325102113 = 1356597399039
BaseRepresentation
bin1111110101111000100…
…11011110101000100001
31221000222221201012110011
413322330103132220201
532404234211231423
61054020504004521
754216612012322
oct7727423365041
91830887635404
10544325102113
1119a9353697a1
12895b1460741
133c43929b350
141c4b9db0449
15e25c1abb0d
hex7ebc4dea21

544325102113 has 8 divisors (see below), whose sum is σ = 586299929600. Its totient is φ = 502365084048.

The previous prime is 544325102107. The next prime is 544325102117. The reversal of 544325102113 is 311201523445.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-544325102113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (544325102117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3625953 + ... + 3773086.

It is an arithmetic number, because the mean of its divisors is an integer number (73287491200).

Almost surely, 2544325102113 is an apocalyptic number.

It is an amenable number.

544325102113 is a deficient number, since it is larger than the sum of its proper divisors (41974827487).

544325102113 is a wasteful number, since it uses less digits than its factorization.

544325102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7404711.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 544325102113 its reverse (311201523445), we get a palindrome (855526625558).

The spelling of 544325102113 in words is "five hundred forty-four billion, three hundred twenty-five million, one hundred two thousand, one hundred thirteen".

Divisors: 1 13 5659 73567 7399039 96187507 41871161701 544325102113