Base | Representation |
---|---|
bin | 1111110101111001011… |
… | …10001101110110001001 |
3 | 1221001000102220022011111 |
4 | 13322330232031312021 |
5 | 32404243010024431 |
6 | 1054021314130321 |
7 | 54220025414152 |
oct | 7727456156611 |
9 | 1831012808144 |
10 | 544332111241 |
11 | 19a939316866 |
12 | 895b38809a1 |
13 | 3c43a883769 |
14 | 1c4bacb6929 |
15 | e25cae37b1 |
hex | 7ebcb8dd89 |
544332111241 has 4 divisors (see below), whose sum is σ = 544502697984. Its totient is φ = 544161524500.
The previous prime is 544332111221. The next prime is 544332111263. The reversal of 544332111241 is 142111233445.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 544332111241 - 211 = 544332109193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (544332111221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85288585 + ... + 85294966.
It is an arithmetic number, because the mean of its divisors is an integer number (136125674496).
Almost surely, 2544332111241 is an apocalyptic number.
It is an amenable number.
544332111241 is a deficient number, since it is larger than the sum of its proper divisors (170586743).
544332111241 is a wasteful number, since it uses less digits than its factorization.
544332111241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170586742.
The product of its digits is 11520, while the sum is 31.
Adding to 544332111241 its reverse (142111233445), we get a palindrome (686443344686).
The spelling of 544332111241 in words is "five hundred forty-four billion, three hundred thirty-two million, one hundred eleven thousand, two hundred forty-one".
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