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544334000381 is a prime number
BaseRepresentation
bin1111110101111001101…
…01011011000011111101
31221001000120110021120122
413322330311123003331
532404244001003011
61054021422424325
754220050442643
oct7727465330375
91831016407518
10544334000381
1119a93a397136
12895b44320a5
133c43b0955b2
141c4bb249193
15e25cd683db
hex7ebcd5b0fd

544334000381 has 2 divisors, whose sum is σ = 544334000382. Its totient is φ = 544334000380.

The previous prime is 544334000323. The next prime is 544334000401. The reversal of 544334000381 is 183000433445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 432557451481 + 111776548900 = 657691^2 + 334330^2 .

It is a cyclic number.

It is not a de Polignac number, because 544334000381 - 214 = 544333983997 is a prime.

It is a super-2 number, since 2×5443340003812 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544334030381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272167000190 + 272167000191.

It is an arithmetic number, because the mean of its divisors is an integer number (272167000191).

Almost surely, 2544334000381 is an apocalyptic number.

It is an amenable number.

544334000381 is a deficient number, since it is larger than the sum of its proper divisors (1).

544334000381 is an equidigital number, since it uses as much as digits as its factorization.

544334000381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 35.

The spelling of 544334000381 in words is "five hundred forty-four billion, three hundred thirty-four million, three hundred eighty-one", and thus it is an aban number.