Base | Representation |
---|---|
bin | 1111110101111001101… |
… | …01011011000011111101 |
3 | 1221001000120110021120122 |
4 | 13322330311123003331 |
5 | 32404244001003011 |
6 | 1054021422424325 |
7 | 54220050442643 |
oct | 7727465330375 |
9 | 1831016407518 |
10 | 544334000381 |
11 | 19a93a397136 |
12 | 895b44320a5 |
13 | 3c43b0955b2 |
14 | 1c4bb249193 |
15 | e25cd683db |
hex | 7ebcd5b0fd |
544334000381 has 2 divisors, whose sum is σ = 544334000382. Its totient is φ = 544334000380.
The previous prime is 544334000323. The next prime is 544334000401. The reversal of 544334000381 is 183000433445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 432557451481 + 111776548900 = 657691^2 + 334330^2 .
It is a cyclic number.
It is not a de Polignac number, because 544334000381 - 214 = 544333983997 is a prime.
It is a super-2 number, since 2×5443340003812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544334030381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272167000190 + 272167000191.
It is an arithmetic number, because the mean of its divisors is an integer number (272167000191).
Almost surely, 2544334000381 is an apocalyptic number.
It is an amenable number.
544334000381 is a deficient number, since it is larger than the sum of its proper divisors (1).
544334000381 is an equidigital number, since it uses as much as digits as its factorization.
544334000381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
The spelling of 544334000381 in words is "five hundred forty-four billion, three hundred thirty-four million, three hundred eighty-one", and thus it is an aban number.
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