Base | Representation |
---|---|
bin | 110010101100100100… |
… | …011100101101001111 |
3 | 12012111122202120011202 |
4 | 302230210130231033 |
5 | 1342440304442341 |
6 | 41001303340115 |
7 | 3634642351361 |
oct | 625444345517 |
9 | 165448676152 |
10 | 54434843471 |
11 | 210a4060648 |
12 | a67215163b |
13 | 51967b2468 |
14 | 28c5718d31 |
15 | 1638db279b |
hex | cac91cb4f |
54434843471 has 2 divisors, whose sum is σ = 54434843472. Its totient is φ = 54434843470.
The previous prime is 54434843381. The next prime is 54434843479. The reversal of 54434843471 is 17434843445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54434843471 - 222 = 54430649167 is a prime.
It is a super-3 number, since 3×544348434713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54434843479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27217421735 + 27217421736.
It is an arithmetic number, because the mean of its divisors is an integer number (27217421736).
Almost surely, 254434843471 is an apocalyptic number.
54434843471 is a deficient number, since it is larger than the sum of its proper divisors (1).
54434843471 is an equidigital number, since it uses as much as digits as its factorization.
54434843471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2580480, while the sum is 47.
The spelling of 54434843471 in words is "fifty-four billion, four hundred thirty-four million, eight hundred forty-three thousand, four hundred seventy-one".
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