Base | Representation |
---|---|
bin | 110010101100111001… |
… | …011001011100000111 |
3 | 12012112001002120021211 |
4 | 302230321121130013 |
5 | 1342443211210421 |
6 | 41002021152251 |
7 | 3635040133111 |
oct | 625471313407 |
9 | 165461076254 |
10 | 54440335111 |
11 | 210a7171598 |
12 | a673b5b687 |
13 | 5197985c56 |
14 | 28c63483b1 |
15 | 16395e99e1 |
hex | cace59707 |
54440335111 has 2 divisors, whose sum is σ = 54440335112. Its totient is φ = 54440335110.
The previous prime is 54440335073. The next prime is 54440335123. The reversal of 54440335111 is 11153304445.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54440335111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54440335711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27220167555 + 27220167556.
It is an arithmetic number, because the mean of its divisors is an integer number (27220167556).
Almost surely, 254440335111 is an apocalyptic number.
54440335111 is a deficient number, since it is larger than the sum of its proper divisors (1).
54440335111 is an equidigital number, since it uses as much as digits as its factorization.
54440335111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 54440335111 its reverse (11153304445), we get a palindrome (65593639556).
The spelling of 54440335111 in words is "fifty-four billion, four hundred forty million, three hundred thirty-five thousand, one hundred eleven".
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