Base | Representation |
---|---|
bin | 1111110110000010111… |
… | …00101110101000100111 |
3 | 1221001012222010020202211 |
4 | 13323001130232220213 |
5 | 32404423310204111 |
6 | 1054033225544251 |
7 | 54222010441543 |
oct | 7730134565047 |
9 | 1831188106684 |
10 | 544411413031 |
11 | 19a97a060432 |
12 | 89616345087 |
13 | 3c45112b0b5 |
14 | 1c4c763aa23 |
15 | e264a5a521 |
hex | 7ec172ea27 |
544411413031 has 2 divisors, whose sum is σ = 544411413032. Its totient is φ = 544411413030.
The previous prime is 544411412989. The next prime is 544411413053. The reversal of 544411413031 is 130314114445.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-544411413031 is a prime.
It is a super-2 number, since 2×5444114130312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 544411412984 and 544411413002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544411413071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272205706515 + 272205706516.
It is an arithmetic number, because the mean of its divisors is an integer number (272205706516).
Almost surely, 2544411413031 is an apocalyptic number.
544411413031 is a deficient number, since it is larger than the sum of its proper divisors (1).
544411413031 is an equidigital number, since it uses as much as digits as its factorization.
544411413031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 544411413031 its reverse (130314114445), we get a palindrome (674725527476).
The spelling of 544411413031 in words is "five hundred forty-four billion, four hundred eleven million, four hundred thirteen thousand, thirty-one".
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