Base | Representation |
---|---|
bin | 100111101000001111111… |
… | …0111101100101110100111 |
3 | 201021200111122210102012011 |
4 | 1033100133313230232213 |
5 | 1203214020111214101 |
6 | 15330040105535051 |
7 | 1101333444361432 |
oct | 117203767545647 |
9 | 21250448712164 |
10 | 5446553226151 |
11 | 180a963339784 |
12 | 73b6b37a4487 |
13 | 3067b935066b |
14 | 14b8865b4819 |
15 | 96a260b8751 |
hex | 4f41fdecba7 |
5446553226151 has 4 divisors (see below), whose sum is σ = 5447778000832. Its totient is φ = 5445328451472.
The previous prime is 5446553226137. The next prime is 5446553226157. The reversal of 5446553226151 is 1516223556445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5446553226151 - 221 = 5446551128999 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5446553226095 and 5446553226104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5446553226157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 612380670 + ... + 612389563.
It is an arithmetic number, because the mean of its divisors is an integer number (1361944500208).
Almost surely, 25446553226151 is an apocalyptic number.
5446553226151 is a deficient number, since it is larger than the sum of its proper divisors (1224774681).
5446553226151 is a wasteful number, since it uses less digits than its factorization.
5446553226151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1224774680.
The product of its digits is 4320000, while the sum is 49.
The spelling of 5446553226151 in words is "five trillion, four hundred forty-six billion, five hundred fifty-three million, two hundred twenty-six thousand, one hundred fifty-one".
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