Base | Representation |
---|---|
bin | 100111101000010011001… |
… | …1010100100100110000011 |
3 | 201021200210022102002100202 |
4 | 1033100212122210212003 |
5 | 1203214231213444141 |
6 | 15330055031235415 |
7 | 1101336246611615 |
oct | 117204632444603 |
9 | 21250708362322 |
10 | 5446663031171 |
11 | 180aa0a31792a |
12 | 73b724518b6b |
13 | 30680601804b |
14 | 14b896dd8db5 |
15 | 96a30a5849b |
hex | 4f4266a4983 |
5446663031171 has 2 divisors, whose sum is σ = 5446663031172. Its totient is φ = 5446663031170.
The previous prime is 5446663031111. The next prime is 5446663031179. The reversal of 5446663031171 is 1711303666445.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5446663031171 is a prime.
It is a super-2 number, since 2×54466630311712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5446663031179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2723331515585 + 2723331515586.
It is an arithmetic number, because the mean of its divisors is an integer number (2723331515586).
Almost surely, 25446663031171 is an apocalyptic number.
5446663031171 is a deficient number, since it is larger than the sum of its proper divisors (1).
5446663031171 is an equidigital number, since it uses as much as digits as its factorization.
5446663031171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 47.
The spelling of 5446663031171 in words is "five trillion, four hundred forty-six billion, six hundred sixty-three million, thirty-one thousand, one hundred seventy-one".
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