Base | Representation |
---|---|
bin | 100111101000010011001… |
… | …1010100100100101000111 |
3 | 201021200210022102002021112 |
4 | 1033100212122210211013 |
5 | 1203214231213443421 |
6 | 15330055031235235 |
7 | 1101336246611501 |
oct | 117204632444507 |
9 | 21250708362245 |
10 | 5446663031111 |
11 | 180aa0a317885 |
12 | 73b724518b1b |
13 | 306806018003 |
14 | 14b896dd8d71 |
15 | 96a30a5845b |
hex | 4f4266a4947 |
5446663031111 has 2 divisors, whose sum is σ = 5446663031112. Its totient is φ = 5446663031110.
The previous prime is 5446663031101. The next prime is 5446663031171. The reversal of 5446663031111 is 1111303666445.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5446663031111 is a prime.
It is a super-2 number, since 2×54466630311112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5446663031101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2723331515555 + 2723331515556.
It is an arithmetic number, because the mean of its divisors is an integer number (2723331515556).
Almost surely, 25446663031111 is an apocalyptic number.
5446663031111 is a deficient number, since it is larger than the sum of its proper divisors (1).
5446663031111 is an equidigital number, since it uses as much as digits as its factorization.
5446663031111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
Adding to 5446663031111 its reverse (1111303666445), we get a palindrome (6557966697556).
The spelling of 5446663031111 in words is "five trillion, four hundred forty-six billion, six hundred sixty-three million, thirty-one thousand, one hundred eleven".
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