Base | Representation |
---|---|
bin | 1111110111001010100… |
… | …00001011100011101001 |
3 | 1221002202211102111001022 |
4 | 13323211100023203221 |
5 | 32412141044302101 |
6 | 1054213004502225 |
7 | 54242623304453 |
oct | 7734520134351 |
9 | 1832684374038 |
10 | 545012103401 |
11 | 1a015813aa57 |
12 | 8976354a975 |
13 | 3c518708c9c |
14 | 1c5433232d3 |
15 | e29c662a1b |
hex | 7ee540b8e9 |
545012103401 has 2 divisors, whose sum is σ = 545012103402. Its totient is φ = 545012103400.
The previous prime is 545012103359. The next prime is 545012103443. The reversal of 545012103401 is 104301210545.
It is a balanced prime because it is at equal distance from previous prime (545012103359) and next prime (545012103443).
It can be written as a sum of positive squares in only one way, i.e., 429616013401 + 115396090000 = 655451^2 + 339700^2 .
It is a cyclic number.
It is not a de Polignac number, because 545012103401 - 214 = 545012087017 is a prime.
It is not a weakly prime, because it can be changed into another prime (545012103491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272506051700 + 272506051701.
It is an arithmetic number, because the mean of its divisors is an integer number (272506051701).
Almost surely, 2545012103401 is an apocalyptic number.
It is an amenable number.
545012103401 is a deficient number, since it is larger than the sum of its proper divisors (1).
545012103401 is an equidigital number, since it uses as much as digits as its factorization.
545012103401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 545012103401 its reverse (104301210545), we get a palindrome (649313313946).
The spelling of 545012103401 in words is "five hundred forty-five billion, twelve million, one hundred three thousand, four hundred one".
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