Base | Representation |
---|---|
bin | 1111110111101111110… |
… | …11010100100110110111 |
3 | 1221010120122221201200112 |
4 | 13323313323110212313 |
5 | 32413311300340201 |
6 | 1054304035533235 |
7 | 54253446304166 |
oct | 7736773244667 |
9 | 1833518851615 |
10 | 545325402551 |
11 | 1a02a8a78276 |
12 | 8983045a21b |
13 | 3c5685b21b7 |
14 | 1c572b993dd |
15 | e2b9dec0bb |
hex | 7ef7ed49b7 |
545325402551 has 2 divisors, whose sum is σ = 545325402552. Its totient is φ = 545325402550.
The previous prime is 545325402529. The next prime is 545325402581. The reversal of 545325402551 is 155204523545.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 545325402551 - 214 = 545325386167 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 545325402499 and 545325402508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (545325402581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272662701275 + 272662701276.
It is an arithmetic number, because the mean of its divisors is an integer number (272662701276).
Almost surely, 2545325402551 is an apocalyptic number.
545325402551 is a deficient number, since it is larger than the sum of its proper divisors (1).
545325402551 is an equidigital number, since it uses as much as digits as its factorization.
545325402551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600000, while the sum is 41.
The spelling of 545325402551 in words is "five hundred forty-five billion, three hundred twenty-five million, four hundred two thousand, five hundred fifty-one".
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