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54552413433503 = 313717389994719
BaseRepresentation
bin11000110011101011110010…
…01110010110111010011111
321011011011022111011222022102
430121311321032112322133
524122241320314333003
6312005011024235315
714330165442222626
oct1431657116267237
9234134274158272
1054552413433503
1116422604228547
126150758a6bb3b
13245936941944b
14d684cac166bd
15649077e1e588
hex319d79396e9f

54552413433503 has 4 divisors (see below), whose sum is σ = 54569803431360. Its totient is φ = 54535023435648.

The previous prime is 54552413433451. The next prime is 54552413433523. The reversal of 54552413433503 is 30533431425545.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54552413433503 - 212 = 54552413429407 is a prime.

It is a super-2 number, since 2×545524134335032 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54552413433523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8694994223 + ... + 8695000496.

It is an arithmetic number, because the mean of its divisors is an integer number (13642450857840).

Almost surely, 254552413433503 is an apocalyptic number.

54552413433503 is a deficient number, since it is larger than the sum of its proper divisors (17389997857).

54552413433503 is a wasteful number, since it uses less digits than its factorization.

54552413433503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17389997856.

The product of its (nonzero) digits is 6480000, while the sum is 47.

The spelling of 54552413433503 in words is "fifty-four trillion, five hundred fifty-two billion, four hundred thirteen million, four hundred thirty-three thousand, five hundred three".

Divisors: 1 3137 17389994719 54552413433503