Base | Representation |
---|---|
bin | 11000110011110001010110… |
… | …11011100011010010011111 |
3 | 21011011110000212000201000011 |
4 | 30121320223123203102133 |
5 | 24122313431212032021 |
6 | 312010223430144051 |
7 | 14330332515145522 |
oct | 1431705333432237 |
9 | 234143025021004 |
10 | 54555403236511 |
11 | 164238a8963821 |
12 | 61512521b2027 |
13 | 2459724970558 |
14 | d686d1d26bb9 |
15 | 6491a064bde1 |
hex | 319e2b6e349f |
54555403236511 has 4 divisors (see below), whose sum is σ = 56436624037800. Its totient is φ = 52674182435224.
The previous prime is 54555403236487. The next prime is 54555403236707. The reversal of 54555403236511 is 11563230455545.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 54555403236511 - 223 = 54555394847903 is a prime.
It is a super-3 number, since 3×545554032365113 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54555403236811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 940610400601 + ... + 940610400658.
It is an arithmetic number, because the mean of its divisors is an integer number (14109156009450).
Almost surely, 254555403236511 is an apocalyptic number.
54555403236511 is a deficient number, since it is larger than the sum of its proper divisors (1881220801289).
54555403236511 is a wasteful number, since it uses less digits than its factorization.
54555403236511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1881220801288.
The product of its (nonzero) digits is 5400000, while the sum is 49.
The spelling of 54555403236511 in words is "fifty-four trillion, five hundred fifty-five billion, four hundred three million, two hundred thirty-six thousand, five hundred eleven".
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