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5462935800041 is a prime number
BaseRepresentation
bin100111101111111000001…
…0110010000100011101001
3201100020210101111101201002
41033133300112100203221
51204001043031100131
615341345453204345
71102453433064506
oct117376026204351
921306711441632
105462935800041
1118168aa927a45
127429061906b5
133081ca456475
1414c59c2924ad
159718447e6cb
hex4f7f05908e9

5462935800041 has 2 divisors, whose sum is σ = 5462935800042. Its totient is φ = 5462935800040.

The previous prime is 5462935800013. The next prime is 5462935800043. The reversal of 5462935800041 is 1400085392645.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4666049290816 + 796886509225 = 2160104^2 + 892685^2 .

It is a cyclic number.

It is not a de Polignac number, because 5462935800041 - 210 = 5462935799017 is a prime.

Together with 5462935800043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5462935800043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2731467900020 + 2731467900021.

It is an arithmetic number, because the mean of its divisors is an integer number (2731467900021).

Almost surely, 25462935800041 is an apocalyptic number.

It is an amenable number.

5462935800041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5462935800041 is an equidigital number, since it uses as much as digits as its factorization.

5462935800041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 47.

The spelling of 5462935800041 in words is "five trillion, four hundred sixty-two billion, nine hundred thirty-five million, eight hundred thousand, forty-one".