Base | Representation |
---|---|
bin | 100111110000100101000… |
… | …1100001100111101011101 |
3 | 201100101200102202211210102 |
4 | 1033201022030030331131 |
5 | 1204012134414111214 |
6 | 15342155220150445 |
7 | 1102535665042025 |
oct | 117411214147535 |
9 | 21311612684712 |
10 | 5464443113309 |
11 | 1817503752794 |
12 | 743066b38425 |
13 | 3083aa8093cb |
14 | 14c6a253aa85 |
15 | 97221970bde |
hex | 4f84a30cf5d |
5464443113309 has 2 divisors, whose sum is σ = 5464443113310. Its totient is φ = 5464443113308.
The previous prime is 5464443113287. The next prime is 5464443113419. The reversal of 5464443113309 is 9033113444645.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3331099516900 + 2133343596409 = 1825130^2 + 1460597^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5464443113309 is a prime.
It is a super-6 number, since 6×54644431133096 (a number of 78 digits) contains 666666 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5464443110309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2732221556654 + 2732221556655.
It is an arithmetic number, because the mean of its divisors is an integer number (2732221556655).
Almost surely, 25464443113309 is an apocalyptic number.
It is an amenable number.
5464443113309 is a deficient number, since it is larger than the sum of its proper divisors (1).
5464443113309 is an equidigital number, since it uses as much as digits as its factorization.
5464443113309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 47.
The spelling of 5464443113309 in words is "five trillion, four hundred sixty-four billion, four hundred forty-three million, one hundred thirteen thousand, three hundred nine".
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