Base | Representation |
---|---|
bin | 110010111001100010… |
… | …000001110111001011 |
3 | 12020001210222011100001 |
4 | 302321202001313023 |
5 | 1343411443004120 |
6 | 41035032423431 |
7 | 3643222665415 |
oct | 627142016713 |
9 | 166053864301 |
10 | 54652313035 |
11 | 211a5895761 |
12 | a712b47b77 |
13 | 51cc875188 |
14 | 29065679b5 |
15 | 164d01ce0a |
hex | cb9881dcb |
54652313035 has 4 divisors (see below), whose sum is σ = 65582775648. Its totient is φ = 43721850424.
The previous prime is 54652312991. The next prime is 54652313057. The reversal of 54652313035 is 53031325645.
54652313035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53031325645 = 5 ⋅10606265129.
It is a cyclic number.
It is not a de Polignac number, because 54652313035 - 235 = 20292574667 is a prime.
It is a super-2 number, since 2×546523130352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54652312985 and 54652313003.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5465231299 + ... + 5465231308.
It is an arithmetic number, because the mean of its divisors is an integer number (16395693912).
Almost surely, 254652313035 is an apocalyptic number.
54652313035 is a deficient number, since it is larger than the sum of its proper divisors (10930462613).
54652313035 is a wasteful number, since it uses less digits than its factorization.
54652313035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10930462612.
The product of its (nonzero) digits is 162000, while the sum is 37.
The spelling of 54652313035 in words is "fifty-four billion, six hundred fifty-two million, three hundred thirteen thousand, thirty-five".
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