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54656066034413 is a prime number
BaseRepresentation
bin11000110110101100110110…
…11001101001101011101101
321011112001212012211200001022
430123112123121221223231
524130441110401100123
6312124352231223525
714340525160622444
oct1433263331515355
9234461765750038
1054656066034413
1116462564439788
126168865b17ba5
1324660778951ac
14d6d520dd9d5b
1564bae2b5b1c8
hex31b59b669aed

54656066034413 has 2 divisors, whose sum is σ = 54656066034414. Its totient is φ = 54656066034412.

The previous prime is 54656066034359. The next prime is 54656066034431. The reversal of 54656066034413 is 31443066065645.

Together with next prime (54656066034431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51408584520484 + 3247481513929 = 7169978^2 + 1802077^2 .

It is a cyclic number.

It is not a de Polignac number, because 54656066034413 - 240 = 53556554406637 is a prime.

It is a super-2 number, since 2×546560660344132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54656066034313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27328033017206 + 27328033017207.

It is an arithmetic number, because the mean of its divisors is an integer number (27328033017207).

Almost surely, 254656066034413 is an apocalyptic number.

It is an amenable number.

54656066034413 is a deficient number, since it is larger than the sum of its proper divisors (1).

54656066034413 is an equidigital number, since it uses as much as digits as its factorization.

54656066034413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18662400, while the sum is 53.

The spelling of 54656066034413 in words is "fifty-four trillion, six hundred fifty-six billion, sixty-six million, thirty-four thousand, four hundred thirteen".