Base | Representation |
---|---|
bin | 11000110110110011110000… |
… | …00111001111111011110101 |
3 | 21011112102102021120112201102 |
4 | 30123121320013033323311 |
5 | 24131021201324200333 |
6 | 312130203510135445 |
7 | 14341016013245042 |
oct | 1433317007177365 |
9 | 234472367515642 |
10 | 54659768975093 |
11 | 16464094677937 |
12 | 616951a051585 |
13 | 2466517aa8459 |
14 | d6d792b041c9 |
15 | 64bc5cca3ae8 |
hex | 31b6781cfef5 |
54659768975093 has 2 divisors, whose sum is σ = 54659768975094. Its totient is φ = 54659768975092.
The previous prime is 54659768975003. The next prime is 54659768975117. The reversal of 54659768975093 is 39057986795645.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41126030309764 + 13533738665329 = 6412958^2 + 3678823^2 .
It is a cyclic number.
It is not a de Polignac number, because 54659768975093 - 224 = 54659752197877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54659768975003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27329884487546 + 27329884487547.
It is an arithmetic number, because the mean of its divisors is an integer number (27329884487547).
Almost surely, 254659768975093 is an apocalyptic number.
It is an amenable number.
54659768975093 is a deficient number, since it is larger than the sum of its proper divisors (1).
54659768975093 is an equidigital number, since it uses as much as digits as its factorization.
54659768975093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15431472000, while the sum is 83.
The spelling of 54659768975093 in words is "fifty-four trillion, six hundred fifty-nine billion, seven hundred sixty-eight million, nine hundred seventy-five thousand, ninety-three".
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