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54720111893 is a prime number
BaseRepresentation
bin110010111101100100…
…101010010100010101
312020020112112200212212
4302331210222110111
51344031322040033
641045453523205
73645005163626
oct627544522425
9166215480785
1054720111893
1121230092a77
12a7317a3505
135210922b45
142911575a4d
151653e61748
hexcbd92a515

54720111893 has 2 divisors, whose sum is σ = 54720111894. Its totient is φ = 54720111892.

The previous prime is 54720111889. The next prime is 54720111907. The reversal of 54720111893 is 39811102745.

54720111893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54689564164 + 30547729 = 233858^2 + 5527^2 .

It is a cyclic number.

It is not a de Polignac number, because 54720111893 - 22 = 54720111889 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 54720111893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54720111833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27360055946 + 27360055947.

It is an arithmetic number, because the mean of its divisors is an integer number (27360055947).

Almost surely, 254720111893 is an apocalyptic number.

It is an amenable number.

54720111893 is a deficient number, since it is larger than the sum of its proper divisors (1).

54720111893 is an equidigital number, since it uses as much as digits as its factorization.

54720111893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 41.

The spelling of 54720111893 in words is "fifty-four billion, seven hundred twenty million, one hundred eleven thousand, eight hundred ninety-three".