Base | Representation |
---|---|
bin | 110010111101100100… |
… | …111010101001111101 |
3 | 12020020112200002200101 |
4 | 302331210322221331 |
5 | 1344031331210223 |
6 | 41045455201101 |
7 | 3645005563006 |
oct | 627544725175 |
9 | 166215602611 |
10 | 54720178813 |
11 | 21230129283 |
12 | a731816191 |
13 | 5210947441 |
14 | 29115921ad |
15 | 1653e764ad |
hex | cbd93aa7d |
54720178813 has 4 divisors (see below), whose sum is σ = 54720653440. Its totient is φ = 54719704188.
The previous prime is 54720178757. The next prime is 54720178819. The reversal of 54720178813 is 31887102745.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 54720178813 - 217 = 54720047741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54720178819) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58708 + ... + 335986.
It is an arithmetic number, because the mean of its divisors is an integer number (13680163360).
Almost surely, 254720178813 is an apocalyptic number.
It is an amenable number.
54720178813 is a deficient number, since it is larger than the sum of its proper divisors (474627).
54720178813 is a wasteful number, since it uses less digits than its factorization.
54720178813 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 474626.
The product of its (nonzero) digits is 376320, while the sum is 46.
The spelling of 54720178813 in words is "fifty-four billion, seven hundred twenty million, one hundred seventy-eight thousand, eight hundred thirteen".
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