Base | Representation |
---|---|
bin | 100111110101110101110… |
… | …0100001110000101100001 |
3 | 201101110211202202022121101 |
4 | 1033223223210032011201 |
5 | 1204203304030210440 |
6 | 15351304225554401 |
7 | 1103415645040531 |
oct | 117535344160541 |
9 | 21343752668541 |
10 | 5475740475745 |
11 | 1821280823361 |
12 | 74529a4a5a01 |
13 | 30948b21a157 |
14 | 14d054ad54c1 |
15 | 9768369c69a |
hex | 4faeb90e161 |
5475740475745 has 4 divisors (see below), whose sum is σ = 6570888570900. Its totient is φ = 4380592380592.
The previous prime is 5475740475721. The next prime is 5475740475761.
5475740475745 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1719675540496 + 3756064935249 = 1311364^2 + 1938057^2 .
It is a cyclic number.
It is not a de Polignac number, because 5475740475745 - 27 = 5475740475617 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547574047570 + ... + 547574047579.
It is an arithmetic number, because the mean of its divisors is an integer number (1642722142725).
Almost surely, 25475740475745 is an apocalyptic number.
It is an amenable number.
5475740475745 is a deficient number, since it is larger than the sum of its proper divisors (1095148095155).
5475740475745 is a wasteful number, since it uses less digits than its factorization.
5475740475745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1095148095154.
The product of its (nonzero) digits is 384160000, while the sum is 64.
The spelling of 5475740475745 in words is "five trillion, four hundred seventy-five billion, seven hundred forty million, four hundred seventy-five thousand, seven hundred forty-five".
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