Base | Representation |
---|---|
bin | 11000111001101111011001… |
… | …11010000110010111100101 |
3 | 21011220001110021200112121202 |
4 | 30130313230322012113211 |
5 | 24134144012223210432 |
6 | 312244344322052245 |
7 | 14351213361000164 |
oct | 1434675472062745 |
9 | 234801407615552 |
10 | 54760512710117 |
11 | 164a2891904085 |
12 | 6184b54aaa085 |
13 | 2472b816cab96 |
14 | d745cc8453db |
15 | 64e6a744e462 |
hex | 31cdece865e5 |
54760512710117 has 2 divisors, whose sum is σ = 54760512710118. Its totient is φ = 54760512710116.
The previous prime is 54760512710087. The next prime is 54760512710203. The reversal of 54760512710117 is 71101721506745.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54456813624196 + 303699085921 = 7379486^2 + 551089^2 .
It is a cyclic number.
It is not a de Polignac number, because 54760512710117 - 26 = 54760512710053 is a prime.
It is a super-3 number, since 3×547605127101173 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54760512718117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27380256355058 + 27380256355059.
It is an arithmetic number, because the mean of its divisors is an integer number (27380256355059).
Almost surely, 254760512710117 is an apocalyptic number.
It is an amenable number.
54760512710117 is a deficient number, since it is larger than the sum of its proper divisors (1).
54760512710117 is an equidigital number, since it uses as much as digits as its factorization.
54760512710117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 411600, while the sum is 47.
The spelling of 54760512710117 in words is "fifty-four trillion, seven hundred sixty billion, five hundred twelve million, seven hundred ten thousand, one hundred seventeen".
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