Base | Representation |
---|---|
bin | 11000111011010011101111… |
… | …01101000010001011001111 |
3 | 21012002012111110020102101110 |
4 | 30131221313231002023033 |
5 | 24141034323004110042 |
6 | 312325213504543103 |
7 | 14355131313164220 |
oct | 1435516755021317 |
9 | 235065443212343 |
10 | 54814380925647 |
11 | 1651371502a772 |
12 | 6193489321a93 |
13 | 2477c8799a525 |
14 | d7705cbc3247 |
15 | 650cab6d709c |
hex | 31da77b422cf |
54814380925647 has 32 divisors (see below), whose sum is σ = 87159169843200. Its totient is φ = 29960346192480.
The previous prime is 54814380925589. The next prime is 54814380925723. The reversal of 54814380925647 is 74652908341845.
It is not a de Polignac number, because 54814380925647 - 212 = 54814380921551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54814380920647) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50951104 + ... + 52015802.
It is an arithmetic number, because the mean of its divisors is an integer number (2723724057600).
It is a 1-persistent number, because it is pandigital, but 2⋅54814380925647 = 109628761851294 is not.
Almost surely, 254814380925647 is an apocalyptic number.
54814380925647 is a deficient number, since it is larger than the sum of its proper divisors (32344788917553).
54814380925647 is a wasteful number, since it uses less digits than its factorization.
54814380925647 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1171323.
The product of its (nonzero) digits is 232243200, while the sum is 66.
The spelling of 54814380925647 in words is "fifty-four trillion, eight hundred fourteen billion, three hundred eighty million, nine hundred twenty-five thousand, six hundred forty-seven".
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