Base | Representation |
---|---|
bin | 1010001101101011… |
… | …01001110100011111 |
3 | 112011011001110220222 |
4 | 11012311221310133 |
5 | 42212224443333 |
6 | 2304041031555 |
7 | 252612306536 |
oct | 50665516437 |
9 | 15134043828 |
10 | 5483437343 |
11 | 23642916aa |
12 | 10904855bb |
13 | 695064ca7 |
14 | 3a038531d |
15 | 2215ec298 |
hex | 146d69d1f |
5483437343 has 2 divisors, whose sum is σ = 5483437344. Its totient is φ = 5483437342.
The previous prime is 5483437339. The next prime is 5483437369. The reversal of 5483437343 is 3437343845.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5483437343 - 22 = 5483437339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5483437294 and 5483437303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5483437303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2741718671 + 2741718672.
It is an arithmetic number, because the mean of its divisors is an integer number (2741718672).
Almost surely, 25483437343 is an apocalyptic number.
5483437343 is a deficient number, since it is larger than the sum of its proper divisors (1).
5483437343 is an equidigital number, since it uses as much as digits as its factorization.
5483437343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1451520, while the sum is 44.
The square root of 5483437343 is about 74050.2352663379. The cubic root of 5483437343 is about 1763.4005088464.
The spelling of 5483437343 in words is "five billion, four hundred eighty-three million, four hundred thirty-seven thousand, three hundred forty-three".
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