Base | Representation |
---|---|
bin | 11000111100111011010101… |
… | …11111011101000011011101 |
3 | 21012021112001210112012120110 |
4 | 30132131222333131003131 |
5 | 24142442231032202443 |
6 | 312410533034240233 |
7 | 14362140543345006 |
oct | 1436355277350335 |
9 | 235245053465513 |
10 | 54870002225373 |
11 | 16535267886475 |
12 | 61a2210886079 |
13 | 24802b02115ba |
14 | d79a17d041ad |
15 | 65246480c233 |
hex | 31e76afdd0dd |
54870002225373 has 64 divisors (see below), whose sum is σ = 79736887296000. Its totient is φ = 33448396193280.
The previous prime is 54870002225371. The next prime is 54870002225417. The reversal of 54870002225373 is 37352220007845.
It is not a de Polignac number, because 54870002225373 - 21 = 54870002225371 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54870002225371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2111915043 + ... + 2111941023.
It is an arithmetic number, because the mean of its divisors is an integer number (1245888864000).
Almost surely, 254870002225373 is an apocalyptic number.
It is an amenable number.
54870002225373 is a deficient number, since it is larger than the sum of its proper divisors (24866885070627).
54870002225373 is a wasteful number, since it uses less digits than its factorization.
54870002225373 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36922.
The product of its (nonzero) digits is 2822400, while the sum is 48.
The spelling of 54870002225373 in words is "fifty-four trillion, eight hundred seventy billion, two million, two hundred twenty-five thousand, three hundred seventy-three".
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