Base | Representation |
---|---|
bin | 100111111011010101001… |
… | …1000101110011101111111 |
3 | 201102121021112021222001211 |
4 | 1033312222120232131333 |
5 | 1204401431123024003 |
6 | 15400534243545251 |
7 | 1104314104034041 |
oct | 117665230563577 |
9 | 21377245258054 |
10 | 5487531845503 |
11 | 1826281737a44 |
12 | 74762b38b227 |
13 | 30a61a095416 |
14 | 14d852b25a91 |
15 | 97b2395b96d |
hex | 4fdaa62e77f |
5487531845503 has 2 divisors, whose sum is σ = 5487531845504. Its totient is φ = 5487531845502.
The previous prime is 5487531845449. The next prime is 5487531845513. The reversal of 5487531845503 is 3055481357845.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5487531845503 - 213 = 5487531837311 is a prime.
It is a super-2 number, since 2×54875318455032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5487531845513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2743765922751 + 2743765922752.
It is an arithmetic number, because the mean of its divisors is an integer number (2743765922752).
Almost surely, 25487531845503 is an apocalyptic number.
5487531845503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5487531845503 is an equidigital number, since it uses as much as digits as its factorization.
5487531845503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320000, while the sum is 58.
The spelling of 5487531845503 in words is "five trillion, four hundred eighty-seven billion, five hundred thirty-one million, eight hundred forty-five thousand, five hundred three".
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